C++ Coding Practice #2

Written on

May 14, 2020

as

Today's C++ coding practice is to check if two numbers are equal without using arithmetic operators or comparison operators.

The Code

Here's the implementation I whipped out in under 5 minutes:

	#include <iostream>

	bool IsEqual(int a, int b) {
	// a b xor
	// 0 0 0 (equal)
	// 0 1 1
	// 1 0 1
	// 1 1 0 (equal)
	return (a^b) == false;
	}

	std::string ToString(bool b) {
	return b ? "True" : "False";
	}

	int main() {
	int a = 4;
	int b = 3;

	std::cout << a << " == " << b << " (" << ToString(IsEqual(a, b)) << ")" << std::endl;

	a = 7;
	b = 7;
	std::cout << a << " == " << b << " (" << ToString(IsEqual(a, b)) << ")" << std::endl;

	return 0;
	}

view raw test.cpp hosted with ❤ by GitHub

You can compile and run this code with the following commandline:

	$ g++ test.cpp && ./a.out
	4 == 3 (False)
	7 == 7 (True)

view raw commandline.txt hosted with ❤ by GitHub

Dev Notes

	//
	// Whenever there is a constraint to not use arithmetic operators
	// in a calculation, I immediately always think of the bitwise
	// operators.
	//
	// As shown in the code, the XOR operator ("exclusive OR") is the
	// right candidate for the job because it has these properties:
	//
	// a b xor
	// ---------------
	// 0 0 0 (equal)
	// 0 1 1
	// 1 0 1
	// 1 1 0 (equal)

view raw dev-notes.cpp hosted with ❤ by GitHub

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Programming

C/C++

Coding Practice

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